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The output of a batch session can be pre-sorted by means of the -s flag.
One can search a domain and the output sorted. The sort occurs along abs(r), s, p1, s2 and then s1. That is, along columns 7, 8, 9, 11, and 10 of the output.
$ ./kspace_t -s --k0min=-2 --l0min=-2 -f 1 --mod3=2
1 -2 1 -1 -1 0 1 0 0 -0.464286 -0.416667
2 -1 1 0 0 0 -1 0 0 0.392857 -0.333333
0 -2 0 -1 -1 0 -1 0 0 0.250000 -0.250000
1 -2 0 -1 -1 0 -1 0 0 0.000000 -0.166667
2 -2 0 -1 -1 0 -1 0 0 -0.392857 -0.083333
2 -2 2 -1 0 2 -1 0 0 0.464286 0.416667
0 -2 1 0 0 0 -3 -1 0 -0.491071 0.472222
0 -1 -1 0 0 0 -3 1 0 0.491071 -0.472222
1 -2 0 -1 1 0 -5 -1 -2 -0.432143 0.433333
2 -2 1 0 0 0 -5 1 -2 0.432143 -0.433333
1 -1 -1 0 0 0 -5 2 2 0.457143 -0.416667
2 -2 0 -1 1 0 -7 -2 0 -0.473214 -0.476190
0 -2 -1 0 0 0 -7 1 0 0.473214 -0.464286
2 -1 -1 0 0 0 -7 3 1 0.404337 -0.369048
0 -2 -2 -1 -1 0 -9 4 0 0.321429 -0.324074
0 -2 -2 -1 0 0 -11 -5 -5 0.385552 -0.318182
1 -2 -2 -1 -1 0 -11 5 -1 0.198864 -0.280303
2 -2 -1 0 0 0 -13 3 -5 0.396978 -0.371795
2 -2 -2 -1 -1 0 -13 6 -2 0.027472 -0.237179
2 -2 -2 -1 0 0 -17 -7 -8 0.288865 -0.230392
2 -2 -2 -1 1 0 -19 -7 -5 0.273966 -0.228070
One can use the SET programme in conjunction with KSPACE. Here, we filter the output.
$ ./kspace_t -s --k0min=-2 --l0min=-2 -f 1 --mod3=2 --rmax=1 | ./set -r | egrep -A 3 -e 'Home|Diff' | egrep -v '^#$|size'
# Homeoclass: absr=1 s=0 p1=0 s2=-5/12
# Diffeoclass: absr=1 s=0 p1=0 s2=-5/12 s1=-13/28
1 -2 1 -1 -1 0 1 0 0 -0.464286 -0.416667
--
# Homeoclass: absr=1 s=0 p1=0 s2=-1/3
# Diffeoclass: absr=1 s=0 p1=0 s2=-1/3 s1=11/28
2 -1 1 0 0 0 -1 0 0 0.392857 -0.333333
--
# Homeoclass: absr=1 s=0 p1=0 s2=-1/4
# Diffeoclass: absr=1 s=0 p1=0 s2=-1/4 s1=1/4
0 -2 0 -1 -1 0 -1 0 0 0.250000 -0.250000
--
# Homeoclass: absr=1 s=0 p1=0 s2=-1/6
# Diffeoclass: absr=1 s=0 p1=0 s2=-1/6 s1=0/1
1 -2 0 -1 -1 0 -1 0 0 0.000000 -0.166667
--
# Homeoclass: absr=1 s=0 p1=0 s2=-1/12
# Diffeoclass: absr=1 s=0 p1=0 s2=-1/12 s1=-11/28
2 -2 0 -1 -1 0 -1 0 0 -0.392857 -0.083333
--
# Homeoclass: absr=1 s=0 p1=0 s2=5/12
# Diffeoclass: absr=1 s=0 p1=0 s2=5/12 s1=13/28
2 -2 2 -1 0 2 -1 0 0 0.464286 0.416667